6w^2=-64w

Solution for 6w^2=-64w equation:

6w^2=-64w

We move all terms to the left:

6w^2-(-64w)=0

We get rid of parentheses

6w^2+64w=0

a = 6; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·6·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*6}=\frac{-128}{12}
=-10+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*6}=\frac{0}{12}
=0
$